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12x+5=15+1/x
We move all terms to the left:
12x+5-(15+1/x)=0
Domain of the equation: x)!=0We add all the numbers together, and all the variables
x!=0/1
x!=0
x∈R
12x-(1/x+15)+5=0
We get rid of parentheses
12x-1/x-15+5=0
We multiply all the terms by the denominator
12x*x-15*x+5*x-1=0
We add all the numbers together, and all the variables
-10x+12x*x-1=0
Wy multiply elements
12x^2-10x-1=0
a = 12; b = -10; c = -1;
Δ = b2-4ac
Δ = -102-4·12·(-1)
Δ = 148
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{148}=\sqrt{4*37}=\sqrt{4}*\sqrt{37}=2\sqrt{37}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-10)-2\sqrt{37}}{2*12}=\frac{10-2\sqrt{37}}{24} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-10)+2\sqrt{37}}{2*12}=\frac{10+2\sqrt{37}}{24} $
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