12x+6=3(4x+2)12x+6=3(4x+2)

Solution for 12x+6=3(4x+2)12x+6=3(4x+2) equation:

12x+6=3(4x+2)12x+6=3(4x+2)

We move all terms to the left:

12x+6-(3(4x+2)12x+6)=0


We calculate terms in parentheses: -(3(4x+2)12x+6), so:

3(4x+2)12x+6

We multiply parentheses

144x^2+72x+6

Back to the equation:

-(144x^2+72x+6)


We get rid of parentheses

-144x^2+12x-72x-6+6=0

We add all the numbers together, and all the variables

-144x^2-60x=0

a = -144; b = -60; c = 0;
Δ = b2-4ac
Δ = -602-4·(-144)·0
Δ = 3600
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{3600}=60$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-60)-60}{2*-144}=\frac{0}{-288}
=0
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-60)+60}{2*-144}=\frac{120}{-288}
=-5/12
$