12x+7=-3(2x-3)+16x

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Solution for 12x+7=-3(2x-3)+16x equation: 



12x+7=-3(2x-3)+16x

We move all terms to the left:

12x+7-(-3(2x-3)+16x)=0



We calculate terms in parentheses: -(-3(2x-3)+16x), so:

-3(2x-3)+16x

We add all the numbers together, and all the variables

16x-3(2x-3)

We multiply parentheses

16x-6x+9

We add all the numbers together, and all the variables

10x+9

Back to the equation:

-(10x+9)



We get rid of parentheses

12x-10x-9+7=0

We add all the numbers together, and all the variables

2x-2=0

We move all terms containing x to the left, all other terms to the right

2x=2

x=2/2

x=1

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