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12x+8-3x-14=3x+6(x-1)
We move all terms to the left:
12x+8-3x-14-(3x+6(x-1))=0
We add all the numbers together, and all the variables
9x-(3x+6(x-1))-6=0
We calculate terms in parentheses: -(3x+6(x-1)), so:We get rid of parentheses
3x+6(x-1)
We multiply parentheses
3x+6x-6
We add all the numbers together, and all the variables
9x-6
Back to the equation:
-(9x-6)
9x-9x+6-6=0
We add all the numbers together, and all the variables
=0
x=0/1
x=0
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