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12x+8-6x=2(3x+4)
We move all terms to the left:
12x+8-6x-(2(3x+4))=0
We add all the numbers together, and all the variables
6x-(2(3x+4))+8=0
We calculate terms in parentheses: -(2(3x+4)), so:We get rid of parentheses
2(3x+4)
We multiply parentheses
6x+8
Back to the equation:
-(6x+8)
6x-6x-8+8=0
We add all the numbers together, and all the variables
=0
x=0/1
x=0
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