12x-(3x+8)+(39-5x)=14+(25-8)-(41-x)

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Solution for 12x-(3x+8)+(39-5x)=14+(25-8)-(41-x) equation: 



12x-(3x+8)+(39-5x)=14+(25-8)-(41-x)

We move all terms to the left:

12x-(3x+8)+(39-5x)-(14+(25-8)-(41-x))=0

We add all the numbers together, and all the variables

12x-(3x+8)+(-5x+39)-(14+17-(-1x+41))=0

We get rid of parentheses

12x-3x-5x-(14+17-(-1x+41))-8+39=0



We calculate terms in parentheses: -(14+17-(-1x+41)), so:

14+17-(-1x+41)

determiningTheFunctionDomain
-(-1x+41)+14+17

We add all the numbers together, and all the variables

-(-1x+41)+31

We get rid of parentheses

1x-41+31

We add all the numbers together, and all the variables

x-10

Back to the equation:

-(x-10)



We add all the numbers together, and all the variables

4x-(x-10)+31=0

We get rid of parentheses

4x-x+10+31=0

We add all the numbers together, and all the variables

3x+41=0

We move all terms containing x to the left, all other terms to the right

3x=-41

x=-41/3

x=-13+2/3

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