12x-(4x-6)=(9x-27)

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Solution for 12x-(4x-6)=(9x-27) equation: 



12x-(4x-6)=(9x-27)

We move all terms to the left:

12x-(4x-6)-((9x-27))=0

We get rid of parentheses

12x-4x-((9x-27))+6=0



We calculate terms in parentheses: -((9x-27)), so:

(9x-27)

We get rid of parentheses

9x-27

Back to the equation:

-(9x-27)



We add all the numbers together, and all the variables

8x-(9x-27)+6=0

We get rid of parentheses

8x-9x+27+6=0

We add all the numbers together, and all the variables

-1x+33=0

We move all terms containing x to the left, all other terms to the right

-x=-33

x=-33/-1

x=+33

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