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12x-(x+3)=2(x+6)+3
We move all terms to the left:
12x-(x+3)-(2(x+6)+3)=0
We get rid of parentheses
12x-x-(2(x+6)+3)-3=0
We calculate terms in parentheses: -(2(x+6)+3), so:We add all the numbers together, and all the variables
2(x+6)+3
We multiply parentheses
2x+12+3
We add all the numbers together, and all the variables
2x+15
Back to the equation:
-(2x+15)
11x-(2x+15)-3=0
We get rid of parentheses
11x-2x-15-3=0
We add all the numbers together, and all the variables
9x-18=0
We move all terms containing x to the left, all other terms to the right
9x=18
x=18/9
x=2
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