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12x-1/5x=4/5x+22
We move all terms to the left:
12x-1/5x-(4/5x+22)=0
Domain of the equation: 5x!=0
x!=0/5
x!=0
x∈R
Domain of the equation: 5x+22)!=0We get rid of parentheses
x∈R
12x-1/5x-4/5x-22=0
We multiply all the terms by the denominator
12x*5x-22*5x-1-4=0
We add all the numbers together, and all the variables
12x*5x-22*5x-5=0
Wy multiply elements
60x^2-110x-5=0
a = 60; b = -110; c = -5;
Δ = b2-4ac
Δ = -1102-4·60·(-5)
Δ = 13300
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{13300}=\sqrt{100*133}=\sqrt{100}*\sqrt{133}=10\sqrt{133}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-110)-10\sqrt{133}}{2*60}=\frac{110-10\sqrt{133}}{120} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-110)+10\sqrt{133}}{2*60}=\frac{110+10\sqrt{133}}{120} $
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