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12x-15=6-7/3x
We move all terms to the left:
12x-15-(6-7/3x)=0
Domain of the equation: 3x)!=0We add all the numbers together, and all the variables
x!=0/1
x!=0
x∈R
12x-(-7/3x+6)-15=0
We get rid of parentheses
12x+7/3x-6-15=0
We multiply all the terms by the denominator
12x*3x-6*3x-15*3x+7=0
Wy multiply elements
36x^2-18x-45x+7=0
We add all the numbers together, and all the variables
36x^2-63x+7=0
a = 36; b = -63; c = +7;
Δ = b2-4ac
Δ = -632-4·36·7
Δ = 2961
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{2961}=\sqrt{9*329}=\sqrt{9}*\sqrt{329}=3\sqrt{329}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-63)-3\sqrt{329}}{2*36}=\frac{63-3\sqrt{329}}{72} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-63)+3\sqrt{329}}{2*36}=\frac{63+3\sqrt{329}}{72} $
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