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12x-19=9(x-2)+3x
We move all terms to the left:
12x-19-(9(x-2)+3x)=0
We calculate terms in parentheses: -(9(x-2)+3x), so:We get rid of parentheses
9(x-2)+3x
We add all the numbers together, and all the variables
3x+9(x-2)
We multiply parentheses
3x+9x-18
We add all the numbers together, and all the variables
12x-18
Back to the equation:
-(12x-18)
12x-12x+18-19=0
We add all the numbers together, and all the variables
-1!=0
There is no solution for this equation
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