12x-1=(9x-15)+(53)

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Solution for 12x-1=(9x-15)+(53) equation: 



12x-1=(9x-15)+(53)

We move all terms to the left:

12x-1-((9x-15)+(53))=0



We calculate terms in parentheses: -((9x-15)+53), so:

(9x-15)+53

We get rid of parentheses

9x-15+53

We add all the numbers together, and all the variables

9x+38

Back to the equation:

-(9x+38)



We get rid of parentheses

12x-9x-38-1=0

We add all the numbers together, and all the variables

3x-39=0

We move all terms containing x to the left, all other terms to the right

3x=39

x=39/3

x=13

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