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12x-1=(9x-15)+(53)
We move all terms to the left:
12x-1-((9x-15)+(53))=0
We calculate terms in parentheses: -((9x-15)+53), so:We get rid of parentheses
(9x-15)+53
We get rid of parentheses
9x-15+53
We add all the numbers together, and all the variables
9x+38
Back to the equation:
-(9x+38)
12x-9x-38-1=0
We add all the numbers together, and all the variables
3x-39=0
We move all terms containing x to the left, all other terms to the right
3x=39
x=39/3
x=13
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