12x-1=7+4(3x-2)

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Solution for 12x-1=7+4(3x-2) equation: 



12x-1=7+4(3x-2)

We move all terms to the left:

12x-1-(7+4(3x-2))=0



We calculate terms in parentheses: -(7+4(3x-2)), so:

7+4(3x-2)

determiningTheFunctionDomain
4(3x-2)+7

We multiply parentheses

12x-8+7

We add all the numbers together, and all the variables

12x-1

Back to the equation:

-(12x-1)



We get rid of parentheses

12x-12x+1-1=0

We add all the numbers together, and all the variables

=0

x=0/1

x=0

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