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12x-2(x+3)=8(5x+1)
We move all terms to the left:
12x-2(x+3)-(8(5x+1))=0
We multiply parentheses
12x-2x-(8(5x+1))-6=0
We calculate terms in parentheses: -(8(5x+1)), so:We add all the numbers together, and all the variables
8(5x+1)
We multiply parentheses
40x+8
Back to the equation:
-(40x+8)
10x-(40x+8)-6=0
We get rid of parentheses
10x-40x-8-6=0
We add all the numbers together, and all the variables
-30x-14=0
We move all terms containing x to the left, all other terms to the right
-30x=14
x=14/-30
x=-7/15
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