12x-2(x+3)=8(5x+1)

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Solution for 12x-2(x+3)=8(5x+1) equation: 



12x-2(x+3)=8(5x+1)

We move all terms to the left:

12x-2(x+3)-(8(5x+1))=0

We multiply parentheses

12x-2x-(8(5x+1))-6=0



We calculate terms in parentheses: -(8(5x+1)), so:

8(5x+1)

We multiply parentheses

40x+8

Back to the equation:

-(40x+8)



We add all the numbers together, and all the variables

10x-(40x+8)-6=0

We get rid of parentheses

10x-40x-8-6=0

We add all the numbers together, and all the variables

-30x-14=0

We move all terms containing x to the left, all other terms to the right

-30x=14

x=14/-30

x=-7/15

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