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12x-24=1/2x+8
We move all terms to the left:
12x-24-(1/2x+8)=0
Domain of the equation: 2x+8)!=0We get rid of parentheses
x∈R
12x-1/2x-8-24=0
We multiply all the terms by the denominator
12x*2x-8*2x-24*2x-1=0
Wy multiply elements
24x^2-16x-48x-1=0
We add all the numbers together, and all the variables
24x^2-64x-1=0
a = 24; b = -64; c = -1;
Δ = b2-4ac
Δ = -642-4·24·(-1)
Δ = 4192
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{4192}=\sqrt{16*262}=\sqrt{16}*\sqrt{262}=4\sqrt{262}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-64)-4\sqrt{262}}{2*24}=\frac{64-4\sqrt{262}}{48} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-64)+4\sqrt{262}}{2*24}=\frac{64+4\sqrt{262}}{48} $
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