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12x-3(2x-4)=12-3(3+x)
We move all terms to the left:
12x-3(2x-4)-(12-3(3+x))=0
We add all the numbers together, and all the variables
12x-3(2x-4)-(12-3(x+3))=0
We multiply parentheses
12x-6x-(12-3(x+3))+12=0
We calculate terms in parentheses: -(12-3(x+3)), so:We add all the numbers together, and all the variables
12-3(x+3)
determiningTheFunctionDomain -3(x+3)+12
We multiply parentheses
-3x-9+12
We add all the numbers together, and all the variables
-3x+3
Back to the equation:
-(-3x+3)
6x-(-3x+3)+12=0
We get rid of parentheses
6x+3x-3+12=0
We add all the numbers together, and all the variables
9x+9=0
We move all terms containing x to the left, all other terms to the right
9x=-9
x=-9/9
x=-1
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