12x-3(x+1)=45-6(x+3)

Solution for 12x-3(x+1)=45-6(x+3) equation:

12x-3(x+1)=45-6(x+3)

We move all terms to the left:

12x-3(x+1)-(45-6(x+3))=0

We multiply parentheses

12x-3x-(45-6(x+3))-3=0


We calculate terms in parentheses: -(45-6(x+3)), so:

45-6(x+3)

determiningTheFunctionDomain
-6(x+3)+45

We multiply parentheses

-6x-18+45

We add all the numbers together, and all the variables

-6x+27

Back to the equation:

-(-6x+27)


We add all the numbers together, and all the variables

9x-(-6x+27)-3=0

We get rid of parentheses

9x+6x-27-3=0

We add all the numbers together, and all the variables

15x-30=0

We move all terms containing x to the left, all other terms to the right

15x=30

x=30/15

x=2