12x-4(2x-10)=6-(x-3)

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Solution for 12x-4(2x-10)=6-(x-3) equation: 



12x-4(2x-10)=6-(x-3)

We move all terms to the left:

12x-4(2x-10)-(6-(x-3))=0

We multiply parentheses

12x-8x-(6-(x-3))+40=0



We calculate terms in parentheses: -(6-(x-3)), so:

6-(x-3)

determiningTheFunctionDomain
-(x-3)+6

We get rid of parentheses

-x+3+6

We add all the numbers together, and all the variables

-1x+9

Back to the equation:

-(-1x+9)



We add all the numbers together, and all the variables

4x-(-1x+9)+40=0

We get rid of parentheses

4x+1x-9+40=0

We add all the numbers together, and all the variables

5x+31=0

We move all terms containing x to the left, all other terms to the right

5x=-31

x=-31/5

x=-6+1/5

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