12x-4(3/9-4)+43-28=10

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Solution for 12x-4(3/9-4)+43-28=10 equation: 



12x-4(3/9-4)+43-28=10

We move all terms to the left:

12x-4(3/9-4)+43-28-(10)=0

determiningTheFunctionDomain
12x+43-28-10-4(3/9-4)=0

We add all the numbers together, and all the variables

12x+5-4(3/9-4)=0

We multiply parentheses

12x+5+16-3/9*4=0

We multiply all the terms by the denominator


12x*9*4-3+5*9*4+16*9*4=0

We add all the numbers together, and all the variables

12x*9*4+753=0

Wy multiply elements

432x*4+753=0

Wy multiply elements

1728x+753=0

We move all terms containing x to the left, all other terms to the right

1728x=-753

x=-753/1728

x=-251/576

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