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12x-4(5x-1)=2(3x+6)-4x
We move all terms to the left:
12x-4(5x-1)-(2(3x+6)-4x)=0
We multiply parentheses
12x-20x-(2(3x+6)-4x)+4=0
We calculate terms in parentheses: -(2(3x+6)-4x), so:We add all the numbers together, and all the variables
2(3x+6)-4x
We add all the numbers together, and all the variables
-4x+2(3x+6)
We multiply parentheses
-4x+6x+12
We add all the numbers together, and all the variables
2x+12
Back to the equation:
-(2x+12)
-8x-(2x+12)+4=0
We get rid of parentheses
-8x-2x-12+4=0
We add all the numbers together, and all the variables
-10x-8=0
We move all terms containing x to the left, all other terms to the right
-10x=8
x=8/-10
x=-4/5
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