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12x-4(x-1)=3(x+1)
We move all terms to the left:
12x-4(x-1)-(3(x+1))=0
We multiply parentheses
12x-4x-(3(x+1))+4=0
We calculate terms in parentheses: -(3(x+1)), so:We add all the numbers together, and all the variables
3(x+1)
We multiply parentheses
3x+3
Back to the equation:
-(3x+3)
8x-(3x+3)+4=0
We get rid of parentheses
8x-3x-3+4=0
We add all the numbers together, and all the variables
5x+1=0
We move all terms containing x to the left, all other terms to the right
5x=-1
x=-1/5
x=-1/5
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