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12x-4(x-3)-3x=3(3x-1)-3
We move all terms to the left:
12x-4(x-3)-3x-(3(3x-1)-3)=0
We add all the numbers together, and all the variables
9x-4(x-3)-(3(3x-1)-3)=0
We multiply parentheses
9x-4x-(3(3x-1)-3)+12=0
We calculate terms in parentheses: -(3(3x-1)-3), so:We add all the numbers together, and all the variables
3(3x-1)-3
We multiply parentheses
9x-3-3
We add all the numbers together, and all the variables
9x-6
Back to the equation:
-(9x-6)
5x-(9x-6)+12=0
We get rid of parentheses
5x-9x+6+12=0
We add all the numbers together, and all the variables
-4x+18=0
We move all terms containing x to the left, all other terms to the right
-4x=-18
x=-18/-4
x=4+1/2
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