12x-4-(8x+3)+(7x-2)=68

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Solution for 12x-4-(8x+3)+(7x-2)=68 equation:


Simplifying
12x + -4 + -1(8x + 3) + (7x + -2) = 68

Reorder the terms:
12x + -4 + -1(3 + 8x) + (7x + -2) = 68
12x + -4 + (3 * -1 + 8x * -1) + (7x + -2) = 68
12x + -4 + (-3 + -8x) + (7x + -2) = 68

Reorder the terms:
12x + -4 + -3 + -8x + (-2 + 7x) = 68

Remove parenthesis around (-2 + 7x)
12x + -4 + -3 + -8x + -2 + 7x = 68

Reorder the terms:
-4 + -3 + -2 + 12x + -8x + 7x = 68

Combine like terms: -4 + -3 = -7
-7 + -2 + 12x + -8x + 7x = 68

Combine like terms: -7 + -2 = -9
-9 + 12x + -8x + 7x = 68

Combine like terms: 12x + -8x = 4x
-9 + 4x + 7x = 68

Combine like terms: 4x + 7x = 11x
-9 + 11x = 68

Solving
-9 + 11x = 68

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '9' to each side of the equation.
-9 + 9 + 11x = 68 + 9

Combine like terms: -9 + 9 = 0
0 + 11x = 68 + 9
11x = 68 + 9

Combine like terms: 68 + 9 = 77
11x = 77

Divide each side by '11'.
x = 7

Simplifying
x = 7

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