12x-4-(8x+3)+(7x-2)=68.

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Solution for 12x-4-(8x+3)+(7x-2)=68. equation:



12x-4-(8x+3)+(7x-2)=68.
We move all terms to the left:
12x-4-(8x+3)+(7x-2)-(68.)=0
We add all the numbers together, and all the variables
12x-(8x+3)+(7x-2)-4-68=0
We add all the numbers together, and all the variables
12x-(8x+3)+(7x-2)-72=0
We get rid of parentheses
12x-8x+7x-3-2-72=0
We add all the numbers together, and all the variables
11x-77=0
We move all terms containing x to the left, all other terms to the right
11x=77
x=77/11
x=7

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