12x-4x-(8x+3)+(7x-2)=68

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Solution for 12x-4x-(8x+3)+(7x-2)=68 equation: 



12x-4x-(8x+3)+(7x-2)=68

We move all terms to the left:

12x-4x-(8x+3)+(7x-2)-(68)=0

We add all the numbers together, and all the variables

8x-(8x+3)+(7x-2)-68=0

We get rid of parentheses

8x-8x+7x-3-2-68=0

We add all the numbers together, and all the variables

7x-73=0

We move all terms containing x to the left, all other terms to the right

7x=73

x=73/7

x=10+3/7

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