12x-5=2(3x-2)+6x-1

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Solution for 12x-5=2(3x-2)+6x-1 equation: 



12x-5=2(3x-2)+6x-1

We move all terms to the left:

12x-5-(2(3x-2)+6x-1)=0



We calculate terms in parentheses: -(2(3x-2)+6x-1), so:

2(3x-2)+6x-1

We add all the numbers together, and all the variables

6x+2(3x-2)-1

We multiply parentheses

6x+6x-4-1

We add all the numbers together, and all the variables

12x-5

Back to the equation:

-(12x-5)



We get rid of parentheses

12x-12x+5-5=0

We add all the numbers together, and all the variables

=0

x=0/1

x=0

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