12x-6=3(2x+20)

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Solution for 12x-6=3(2x+20) equation: 



12x-6=3(2x+20)

We move all terms to the left:

12x-6-(3(2x+20))=0



We calculate terms in parentheses: -(3(2x+20)), so:

3(2x+20)

We multiply parentheses

6x+60

Back to the equation:

-(6x+60)



We get rid of parentheses

12x-6x-60-6=0

We add all the numbers together, and all the variables

6x-66=0

We move all terms containing x to the left, all other terms to the right

6x=66

x=66/6

x=11

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