12x-9x+108-68=16x+6

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Solution for 12x-9x+108-68=16x+6 equation: 



12x-9x+108-68=16x+6

We move all terms to the left:

12x-9x+108-68-(16x+6)=0

We add all the numbers together, and all the variables

3x-(16x+6)+40=0

We get rid of parentheses

3x-16x-6+40=0

We add all the numbers together, and all the variables

-13x+34=0

We move all terms containing x to the left, all other terms to the right

-13x=-34

x=-34/-13

x=2+8/13

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