12x-y=1;28x+1/3y=1

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Remember to put linear equations with variables x and y.
for example:
2x+y=8
x+3y=14

Solution for 12x-y=1;28x+1/3y=1 system of equations: 


  • /| 12*x-y-1 = 0| 28*x+(1/3)*y-1 = 0
  • We try to solve the equation: 12*x-y-1 = 0
  • 12*x-y-1 = 0 // - 12*x-1
  • -y = -(12*x-1) // * -1
  • y = 12*x-1
  • We insert the solution into one of the initial equations of our system of equations
  • We get a system of equations:
  • /| (1/3)*(12*x-1)+28*x-1 = 0| y = 12*x-1
  • 1/3*(12*x-1)+28*x-1 = 0
  • 32*x-1-1/3 = 0
  • 32*x-4/3 = 0
  • 32*x-4/3 = 0 // + 4/3
  • 32*x = 4/3 // : 32
  • x = 4/3/32
  • x = 1/24
  • We insert the solution into one of the initial equations of our system of equations
  • For y = 12*x-1: 
  • y = 1/24*12-1
  • y = 1/2-1
  • y = -1/2
  • We get a system of equations:
  • /| y = -1/2| x = 1/24

 

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