12x/2=(6x+36)/3

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Solution for 12x/2=(6x+36)/3 equation: 



12x/2=(6x+36)/3

We move all terms to the left:

12x/2-((6x+36)/3)=0

We calculate fractions


36x^2/()+(-((6x+36)*2)/()=0



We calculate terms in parentheses: +(-((6x+36)*2)/(), so:

-((6x+36)*2)/(

We multiply all the terms by the denominator


-((6x+36)*2)



We calculate terms in parentheses: -((6x+36)*2), so:

(6x+36)*2

We multiply parentheses

12x+72

Back to the equation:

-(12x+72)



We get rid of parentheses

-12x-72

Back to the equation:

+(-12x-72)



We get rid of parentheses

36x^2/()-12x-72=0

We multiply all the terms by the denominator


36x^2-12x*()-72*()=0

We add all the numbers together, and all the variables

36x^2-12x*()=0

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