If it's not what You are looking for type in the equation solver your own equation and let us solve it.
12x^2+-36x+32=0
We add all the numbers together, and all the variables
12x^2-36x=0
a = 12; b = -36; c = 0;
Δ = b2-4ac
Δ = -362-4·12·0
Δ = 1296
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{1296}=36$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-36)-36}{2*12}=\frac{0}{24} =0 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-36)+36}{2*12}=\frac{72}{24} =3 $
| 2/3x=3/4=8 | | 31/2-2x=11/4 | | –2.5p–20=9p+37.5 | | x3+12x2+-36x+32=0 | | p=(10–Q)+(1–0.1Q) | | 14x-182=5x-11 | | x^2+3x-1/x+4= | | 4x-182=5x-11 | | x^2+3x-1/x=4 | | 2.5(–3p–8)+5p=4(2.25p+5.5)+15.5 | | 6x/8-4=20 | | e=4e+10 | | 3/2x+6/3=2/4 | | 0.9(x+60)+0.5x=103 | | -16t^2+60t+40=0 | | 5x-4x=24 | | 0(t)=-16t^2+60t+40 | | 12x²+11x+2=0 | | 6(t-2)+6t=4(3t+5)-11 | | X+3(x+5)=x-4 | | 2-g=-14 | | x-0.4x=1.5 | | 20=4(u+1) | | -11=u/2-14 | | 11z/16+7z/8=50/16 | | x+x+0.27+x+0.27+0.34=9.91 | | 5(y-1)=3(2y-5)-(1-3y | | x4-3x3-x2+3x=0 | | 60=-u–4u | | k^2-7k=11 | | k^2-2k=5k+11 | | v-8/3=2 |