12x2+-41x+35=0

Solution for 12x2+-41x+35=0 equation:

12x^2+-41x+35=0

We add all the numbers together, and all the variables

12x^2-41x=0

a = 12; b = -41; c = 0;
Δ = b2-4ac
Δ = -412-4·12·0
Δ = 1681
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1681}=41$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-41)-41}{2*12}=\frac{0}{24}
=0
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-41)+41}{2*12}=\frac{82}{24}
=3+5/12
$