If it's not what You are looking for type in the equation solver your own equation and let us solve it.
12x^2+12x-9=0
a = 12; b = 12; c = -9;
Δ = b2-4ac
Δ = 122-4·12·(-9)
Δ = 576
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{576}=24$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(12)-24}{2*12}=\frac{-36}{24} =-1+1/2 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(12)+24}{2*12}=\frac{12}{24} =1/2 $
| -14(-2x+2)=-252 | | 2321=11(2+11x) | | (12)3=x | | 3+12+5g=35 | | 2x^2+11x+5=()() | | 6y-60=y | | 3m+9=m=12 | | 1-9x/3-2=x/3-11x-1/2/ | | x+(-6)=24 | | 6=-16t^2-20t-40 | | 100-27=c+43 | | (2b)^2=1 | | 5x-47=x | | x/12=11x-10 | | x+6+54=90 | | 3(p+7)-(4p-1=-5(2p-3)+1 | | 6x-46=x | | -4*10^-5x=-100 | | 8^(9x-8)=7^(6x-2) | | 4^m+1=2000 | | 12x5=60 | | H(f)=1.88f+32.01 | | 3m+8-4m-3+6m=25 | | 0.7(15x-30)=-3/2(3x+14)+15x | | 8=-6-2r | | 8c-7=5c+18 | | 1/2(14x-38)=3.5(2x-6) | | g+1=-7 | | 21=4x–9–x3(x+1)=6 | | -6n+25=17 | | 3x+4(5x-6)=7(x+8)-9x | | c÷4=-3 |