12x2+18x+6=0

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Solution for 12x2+18x+6=0 equation:



12x^2+18x+6=0
a = 12; b = 18; c = +6;
Δ = b2-4ac
Δ = 182-4·12·6
Δ = 36
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{36}=6$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(18)-6}{2*12}=\frac{-24}{24} =-1 $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(18)+6}{2*12}=\frac{-12}{24} =-1/2 $

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