12x2+24x-87=0

Solution for 12x2+24x-87=0 equation:

12x^2+24x-87=0

a = 12; b = 24; c = -87;
Δ = b2-4ac
Δ = 242-4·12·(-87)
Δ = 4752
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{4752}=\sqrt{144*33}=\sqrt{144}*\sqrt{33}=12\sqrt{33}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(24)-12\sqrt{33}}{2*12}=\frac{-24-12\sqrt{33}}{24}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(24)+12\sqrt{33}}{2*12}=\frac{-24+12\sqrt{33}}{24}
$