If it's not what You are looking for type in the equation solver your own equation and let us solve it.
12x^2+2x=8
We move all terms to the left:
12x^2+2x-(8)=0
a = 12; b = 2; c = -8;
Δ = b2-4ac
Δ = 22-4·12·(-8)
Δ = 388
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{388}=\sqrt{4*97}=\sqrt{4}*\sqrt{97}=2\sqrt{97}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(2)-2\sqrt{97}}{2*12}=\frac{-2-2\sqrt{97}}{24} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(2)+2\sqrt{97}}{2*12}=\frac{-2+2\sqrt{97}}{24} $
| 15x^2-36x=0 | | 5(m-2)+8m=94 | | 13×-2l=1/2 | | 3d+4–9d+12=(–5d) | | 4=2(−x−3) | | -8 x + (-18) = 54 | | (10x+5)45= | | 30c-12-10c=13 | | 3d+4–9d+12=–5d | | -3+2p=17 | | 54=39-y | | 7=9x+8 | | 32x^2-48x+16=0 | | (5x+4)(x+2)=180 | | n–12=23 | | y/8-17=13 | | y+3(2-y)=8* | | 2+8k+5=23 | | 6(m-6)=9(m-9) | | -3/2y+5=2 | | −3(2r−8)=6 | | -4+2b=-2 | | -14.3=-1.4+-3y | | 5(4+x)=7x-2* | | -14.3=-1.4-3y | | 18=−3(x+2) | | -x+10=-2(x-2) | | 7(3w+3)/4=-9 | | (x-0.3)(2x-0.5)=0 | | 13=w/2 | | 17+4x=-4 | | 30=-3(x–1) |