12x2+4x=8

Solution for 12x2+4x=8 equation:

12x^2+4x=8

We move all terms to the left:

12x^2+4x-(8)=0

a = 12; b = 4; c = -8;
Δ = b2-4ac
Δ = 42-4·12·(-8)
Δ = 400
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{400}=20$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(4)-20}{2*12}=\frac{-24}{24}
=-1
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(4)+20}{2*12}=\frac{16}{24}
=2/3
$