If it's not what You are looking for type in the equation solver your own equation and let us solve it.
12x^2+5x-2=0
a = 12; b = 5; c = -2;
Δ = b2-4ac
Δ = 52-4·12·(-2)
Δ = 121
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{121}=11$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(5)-11}{2*12}=\frac{-16}{24} =-2/3 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(5)+11}{2*12}=\frac{6}{24} =1/4 $
| 9-2w/6=13/18 | | -6x+2=-2-6x | | c/2+3=6 | | |x/4|=18 | | 4x-3=-2+4x | | 50-10x=40-4x | | 3x+11=3(x-1.5) | | 25/4x=9 | | -7(-x-8)+4(1+7x)=-80 | | 8p+7(3-p)-(4p-1)+8=-1 | | 5x+3+14x+6=180 | | u-6.48=4.78 | | -4p-(1-6p=) | | B=5/2(j-13) | | -4=-13-n | | 3n+5–3(1-7n)=5+7n | | -12=2/5t | | 32=12+4(z-1 | | 17=n/5 | | 3/5m=3/4 | | -52=23-5s | | 6−3y=−6 | | 3(h–6)=2(5–2h) | | F(x)=3x3+ | | F(x)=3×3+8x2+4x | | p-20/100=28.78 | | x+61+x+61+80=180 | | 5-2x/3=12 | | 12=2(2f+3)+2 | | 3-4(y+2)=6+4(2y+1) | | 11y-7+6=0 | | 3-4y+8=6+8y+4 |