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12x^2+69x+45=0
a = 12; b = 69; c = +45;
Δ = b2-4ac
Δ = 692-4·12·45
Δ = 2601
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{2601}=51$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(69)-51}{2*12}=\frac{-120}{24} =-5 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(69)+51}{2*12}=\frac{-18}{24} =-3/4 $
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