12x2+80x=-100

Solution for 12x2+80x=-100 equation:

12x^2+80x=-100

We move all terms to the left:

12x^2+80x-(-100)=0

We add all the numbers together, and all the variables

12x^2+80x+100=0

a = 12; b = 80; c = +100;
Δ = b2-4ac
Δ = 802-4·12·100
Δ = 1600
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1600}=40$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(80)-40}{2*12}=\frac{-120}{24}
=-5
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(80)+40}{2*12}=\frac{-40}{24}
=-1+2/3
$