12x2-(3x-4)(4x+1)=19

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Solution for 12x2-(3x-4)(4x+1)=19 equation: 



12x^2-(3x-4)(4x+1)=19

We move all terms to the left:

12x^2-(3x-4)(4x+1)-(19)=0

We multiply parentheses ..

12x^2-(+12x^2+3x-16x-4)-19=0

We get rid of parentheses

12x^2-12x^2-3x+16x+4-19=0

We add all the numbers together, and all the variables

13x-15=0

We move all terms containing x to the left, all other terms to the right

13x=15

x=15/13

x=1+2/13

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