If it's not what You are looking for type in the equation solver your own equation and let us solve it.
12x^2-13x-20=0
a = 12; b = -13; c = -20;
Δ = b2-4ac
Δ = -132-4·12·(-20)
Δ = 1129
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-13)-\sqrt{1129}}{2*12}=\frac{13-\sqrt{1129}}{24} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-13)+\sqrt{1129}}{2*12}=\frac{13+\sqrt{1129}}{24} $
| 20x2-15x-13=0 | | 4x2-2x-7=0 | | 9x2-2x+7=0 | | 19x2-13x+7=0 | | 10x2-10x-2=0 | | 11x2-7x-7=0 | | 14x2-11x+16=0 | | x2-x-17=0 | | 14x2-3x+6=0 | | 4x2-14x-9=0 | | 11x2-11x-3=0 | | 14x2+4x-13=0 | | 16x2+13x+6=0 | | 6x=48= | | 5y^2+14y-8=0 | | 6x^2-31x+15=0 | | 3x(2x+5)=15 | | x2+11x+34=4 | | -5+3f=7 | | -4-3(4x+2)=3(5-2x)+1 | | 2x/3-x/3=x/4+3/2 | | n/2+n/3=35-n+30/5 | | 3(3x+5)+5(2x-9)=3(4x-3)-15 | | 5n-4/5=20 | | 2p-1=p+12 | | 10b+10=-5+7b | | 84x-17x-67=0 | | 3x+12=7-40 | | -7t=-8t-3 | | x/10+(x+8)/2=2x/5+5 | | 9y-5=24 | | x^2+16x+260=0 |