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12x^2-13x-69=0
a = 12; b = -13; c = -69;
Δ = b2-4ac
Δ = -132-4·12·(-69)
Δ = 3481
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{3481}=59$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-13)-59}{2*12}=\frac{-46}{24} =-1+11/12 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-13)+59}{2*12}=\frac{72}{24} =3 $
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