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12x^2-15=0
a = 12; b = 0; c = -15;
Δ = b2-4ac
Δ = 02-4·12·(-15)
Δ = 720
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{720}=\sqrt{144*5}=\sqrt{144}*\sqrt{5}=12\sqrt{5}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-12\sqrt{5}}{2*12}=\frac{0-12\sqrt{5}}{24} =-\frac{12\sqrt{5}}{24} =-\frac{\sqrt{5}}{2} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+12\sqrt{5}}{2*12}=\frac{0+12\sqrt{5}}{24} =\frac{12\sqrt{5}}{24} =\frac{\sqrt{5}}{2} $
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