12x2-22x-42=0

Solution for 12x2-22x-42=0 equation:

12x^2-22x-42=0

a = 12; b = -22; c = -42;
Δ = b2-4ac
Δ = -222-4·12·(-42)
Δ = 2500
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{2500}=50$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-22)-50}{2*12}=\frac{-28}{24}
=-1+1/6
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-22)+50}{2*12}=\frac{72}{24}
=3
$