12x2-5=-6x2+3

Solution for 12x2-5=-6x2+3 equation:

12x^2-5=-6x^2+3

We move all terms to the left:

12x^2-5-(-6x^2+3)=0

We get rid of parentheses

12x^2+6x^2-3-5=0

We add all the numbers together, and all the variables

18x^2-8=0

a = 18; b = 0; c = -8;
Δ = b2-4ac
Δ = 02-4·18·(-8)
Δ = 576
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{576}=24$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-24}{2*18}=\frac{-24}{36}
=-2/3
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+24}{2*18}=\frac{24}{36}
=2/3
$