12x2-72x+12=0

Solution for 12x2-72x+12=0 equation:

12x^2-72x+12=0

a = 12; b = -72; c = +12;
Δ = b2-4ac
Δ = -722-4·12·12
Δ = 4608
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{4608}=\sqrt{2304*2}=\sqrt{2304}*\sqrt{2}=48\sqrt{2}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-72)-48\sqrt{2}}{2*12}=\frac{72-48\sqrt{2}}{24}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-72)+48\sqrt{2}}{2*12}=\frac{72+48\sqrt{2}}{24}
$