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12x^2-88x+28=0
a = 12; b = -88; c = +28;
Δ = b2-4ac
Δ = -882-4·12·28
Δ = 6400
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{6400}=80$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-88)-80}{2*12}=\frac{8}{24} =1/3 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-88)+80}{2*12}=\frac{168}{24} =7 $
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