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12x^2=192
We move all terms to the left:
12x^2-(192)=0
a = 12; b = 0; c = -192;
Δ = b2-4ac
Δ = 02-4·12·(-192)
Δ = 9216
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{9216}=96$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-96}{2*12}=\frac{-96}{24} =-4 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+96}{2*12}=\frac{96}{24} =4 $
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