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12x^2=36
We move all terms to the left:
12x^2-(36)=0
a = 12; b = 0; c = -36;
Δ = b2-4ac
Δ = 02-4·12·(-36)
Δ = 1728
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{1728}=\sqrt{576*3}=\sqrt{576}*\sqrt{3}=24\sqrt{3}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-24\sqrt{3}}{2*12}=\frac{0-24\sqrt{3}}{24} =-\frac{24\sqrt{3}}{24} =-\sqrt{3} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+24\sqrt{3}}{2*12}=\frac{0+24\sqrt{3}}{24} =\frac{24\sqrt{3}}{24} =\sqrt{3} $
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